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c++ - What does (~0L) mean? - Stack Overflow
0L is a long integer value with all the bits set to zero - that's generally the definition of 0. The ~ means to invert all the bits, which leaves you with a long integer with all the bits set to one. In two's complement arithmetic (which is almost universal) a signed value with all bits set to one is -1.

factorial - Why does 0! = 1? - Mathematics Stack Exchange
$\begingroup$ The theorem that $\binom{n}{k} = \frac{n!}{k!(n-k)!}$ already assumes $0!$ is defined to be $1$. Otherwise this would be restricted to $0

What is the difference between NULL, '\\0' and 0?
NULL is not guaranteed to be 0 -- its exact value is architecture-dependent. Most major architectures define it to (void*)0. '\0' will always equal 0, because that is how byte 0 is encoded in a character literal. I don't remember whether C compilers are required to use ASCII -- if not, '0' might not always equal 48.

windows - Can't access 127.0.0.1 - Stack Overflow
Good question. Just checked redis and it does work on 127.0.0.1. I guess it's because it doesn't use http, but it's special protocol RESP. Will update the question now. To the second part, this is not browser issue, Fiddler (for IIS) and Visual Studio Server Explorer (for azure emulator) both can't connect to 127.0.0.1. –

upgrade Android Gradle Plugin (AGP) versions - Stack Overflow
0 I have faced same issue and now i resolved by the following steps. -If your JAVA_HOME path or flutter jdk path not in java 21, set JAVA_HOME or run a command "flutter config --jdk-dir " to set flutter jdk path to Java 21.

What is %0|%0 and how does it work? - Stack Overflow
@Pavel: What a .bat file does is: read instruction, at the end of file terminate. If you run %0: Process 1: starts, run %0 (thus create process 2); then die Process 2: starts, run %0 (thus create process 3); then die [...] you alway have at most 2 process running because the creator will die.

c - What do 0LL or 0x0UL mean? - Stack Overflow
LL designates a literal as a long long and UL designates one as unsigned long and 0x0 is hexadecimal for 0. So 0LL and 0x0UL are an equivalent number but different datatypes; the former is a long long and the latter is an unsigned long. There are many of these specifiers: 1F // float 1L // long 1ull // unsigned long long 1.0 // double

JSONDecodeError: Expecting value: line 1 column 1 (char 0)
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)... During handling of the above exception, another exception occurred: requests.exceptions.JSONDecodeError: [Errno Expecting value] : 0. Therefore, when performing HEAD requests, make sure that there is a body in the response (which normally there isn't), before calling r ...

Add leading zeroes/0's to existing Excel values to certain length
For those with my issue above, the answer was to swap out # (hash) for 0 (zero). The # gives you no character when there's no value but the 0 gives you a zero when there's no value! Makes sense and works great: $0.0,,"M" –

c - why is *pp[0] equal to **pp - Stack Overflow
For example, int i, j=0; i=j; effectively dereferences j; j is an address constant, and the assignment concerns the value stored there, j's value, so that the assignment amounts to i=0. Other languages, like Algol68, were more precise: one would effectively write int i; int *pi = i; , which makes complete sense (pi now points to i).

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